Optimal. Leaf size=151 \[ \frac{5 a^4 (8 A+7 B) \tan (c+d x)}{8 d}+\frac{a^4 (48 A+35 B) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(4 A+7 B) \tan (c+d x) \left (a^2 \sec (c+d x)+a^2\right )^2}{12 d}+\frac{(32 A+35 B) \tan (c+d x) \left (a^4 \sec (c+d x)+a^4\right )}{24 d}+a^4 A x+\frac{a B \tan (c+d x) (a \sec (c+d x)+a)^3}{4 d} \]
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Rubi [A] time = 0.214004, antiderivative size = 151, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {3917, 3914, 3767, 8, 3770} \[ \frac{5 a^4 (8 A+7 B) \tan (c+d x)}{8 d}+\frac{a^4 (48 A+35 B) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(4 A+7 B) \tan (c+d x) \left (a^2 \sec (c+d x)+a^2\right )^2}{12 d}+\frac{(32 A+35 B) \tan (c+d x) \left (a^4 \sec (c+d x)+a^4\right )}{24 d}+a^4 A x+\frac{a B \tan (c+d x) (a \sec (c+d x)+a)^3}{4 d} \]
Antiderivative was successfully verified.
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Rule 3917
Rule 3914
Rule 3767
Rule 8
Rule 3770
Rubi steps
\begin{align*} \int (a+a \sec (c+d x))^4 (A+B \sec (c+d x)) \, dx &=\frac{a B (a+a \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac{1}{4} \int (a+a \sec (c+d x))^3 (4 a A+a (4 A+7 B) \sec (c+d x)) \, dx\\ &=\frac{a B (a+a \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac{(4 A+7 B) \left (a^2+a^2 \sec (c+d x)\right )^2 \tan (c+d x)}{12 d}+\frac{1}{12} \int (a+a \sec (c+d x))^2 \left (12 a^2 A+a^2 (32 A+35 B) \sec (c+d x)\right ) \, dx\\ &=\frac{a B (a+a \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac{(4 A+7 B) \left (a^2+a^2 \sec (c+d x)\right )^2 \tan (c+d x)}{12 d}+\frac{(32 A+35 B) \left (a^4+a^4 \sec (c+d x)\right ) \tan (c+d x)}{24 d}+\frac{1}{24} \int (a+a \sec (c+d x)) \left (24 a^3 A+15 a^3 (8 A+7 B) \sec (c+d x)\right ) \, dx\\ &=a^4 A x+\frac{a B (a+a \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac{(4 A+7 B) \left (a^2+a^2 \sec (c+d x)\right )^2 \tan (c+d x)}{12 d}+\frac{(32 A+35 B) \left (a^4+a^4 \sec (c+d x)\right ) \tan (c+d x)}{24 d}+\frac{1}{8} \left (5 a^4 (8 A+7 B)\right ) \int \sec ^2(c+d x) \, dx+\frac{1}{8} \left (a^4 (48 A+35 B)\right ) \int \sec (c+d x) \, dx\\ &=a^4 A x+\frac{a^4 (48 A+35 B) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{a B (a+a \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac{(4 A+7 B) \left (a^2+a^2 \sec (c+d x)\right )^2 \tan (c+d x)}{12 d}+\frac{(32 A+35 B) \left (a^4+a^4 \sec (c+d x)\right ) \tan (c+d x)}{24 d}-\frac{\left (5 a^4 (8 A+7 B)\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{8 d}\\ &=a^4 A x+\frac{a^4 (48 A+35 B) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{5 a^4 (8 A+7 B) \tan (c+d x)}{8 d}+\frac{a B (a+a \sec (c+d x))^3 \tan (c+d x)}{4 d}+\frac{(4 A+7 B) \left (a^2+a^2 \sec (c+d x)\right )^2 \tan (c+d x)}{12 d}+\frac{(32 A+35 B) \left (a^4+a^4 \sec (c+d x)\right ) \tan (c+d x)}{24 d}\\ \end{align*}
Mathematica [B] time = 1.75681, size = 326, normalized size = 2.16 \[ \frac{a^4 \sec ^8\left (\frac{1}{2} (c+d x)\right ) (\sec (c+d x)+1)^4 \left (\sec (c) (48 A \sin (2 c+d x)+496 A \sin (c+2 d x)-144 A \sin (3 c+2 d x)+48 A \sin (2 c+3 d x)+48 A \sin (4 c+3 d x)+160 A \sin (3 c+4 d x)+72 A d x \cos (c)+48 A d x \cos (c+2 d x)+48 A d x \cos (3 c+2 d x)+12 A d x \cos (3 c+4 d x)+12 A d x \cos (5 c+4 d x)-480 A \sin (c)+48 A \sin (d x)+105 B \sin (2 c+d x)+544 B \sin (c+2 d x)-96 B \sin (3 c+2 d x)+81 B \sin (2 c+3 d x)+81 B \sin (4 c+3 d x)+160 B \sin (3 c+4 d x)-480 B \sin (c)+105 B \sin (d x))-24 (48 A+35 B) \cos ^4(c+d x) \left (\log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )\right )}{3072 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.055, size = 204, normalized size = 1.4 \begin{align*}{a}^{4}Ax+{\frac{A{a}^{4}c}{d}}+{\frac{35\,B{a}^{4}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+6\,{\frac{A{a}^{4}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{20\,B{a}^{4}\tan \left ( dx+c \right ) }{3\,d}}+{\frac{20\,A{a}^{4}\tan \left ( dx+c \right ) }{3\,d}}+{\frac{27\,B{a}^{4}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{8\,d}}+2\,{\frac{A{a}^{4}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{d}}+{\frac{4\,B{a}^{4}\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}}+{\frac{A{a}^{4}\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}}+{\frac{B{a}^{4}\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{3}}{4\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.04173, size = 396, normalized size = 2.62 \begin{align*} \frac{16 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} A a^{4} + 48 \,{\left (d x + c\right )} A a^{4} + 64 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B a^{4} - 3 \, B a^{4}{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 48 \, A a^{4}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 72 \, B a^{4}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 192 \, A a^{4} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 48 \, B a^{4} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 288 \, A a^{4} \tan \left (d x + c\right ) + 192 \, B a^{4} \tan \left (d x + c\right )}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.511573, size = 408, normalized size = 2.7 \begin{align*} \frac{48 \, A a^{4} d x \cos \left (d x + c\right )^{4} + 3 \,{\left (48 \, A + 35 \, B\right )} a^{4} \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left (48 \, A + 35 \, B\right )} a^{4} \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (160 \,{\left (A + B\right )} a^{4} \cos \left (d x + c\right )^{3} + 3 \,{\left (16 \, A + 27 \, B\right )} a^{4} \cos \left (d x + c\right )^{2} + 8 \,{\left (A + 4 \, B\right )} a^{4} \cos \left (d x + c\right ) + 6 \, B a^{4}\right )} \sin \left (d x + c\right )}{48 \, d \cos \left (d x + c\right )^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} a^{4} \left (\int A\, dx + \int 4 A \sec{\left (c + d x \right )}\, dx + \int 6 A \sec ^{2}{\left (c + d x \right )}\, dx + \int 4 A \sec ^{3}{\left (c + d x \right )}\, dx + \int A \sec ^{4}{\left (c + d x \right )}\, dx + \int B \sec{\left (c + d x \right )}\, dx + \int 4 B \sec ^{2}{\left (c + d x \right )}\, dx + \int 6 B \sec ^{3}{\left (c + d x \right )}\, dx + \int 4 B \sec ^{4}{\left (c + d x \right )}\, dx + \int B \sec ^{5}{\left (c + d x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.33957, size = 301, normalized size = 1.99 \begin{align*} \frac{24 \,{\left (d x + c\right )} A a^{4} + 3 \,{\left (48 \, A a^{4} + 35 \, B a^{4}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 3 \,{\left (48 \, A a^{4} + 35 \, B a^{4}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (120 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 105 \, B a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 424 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 385 \, B a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 520 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 511 \, B a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 216 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 279 \, B a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{4}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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